3x^2-(2x-4)=3+3x^2

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Solution for 3x^2-(2x-4)=3+3x^2 equation: 


Simplifying
3x2 + -1(2x + -4) = 3 + 3x2

Reorder the terms:
3x2 + -1(-4 + 2x) = 3 + 3x2
3x2 + (-4 * -1 + 2x * -1) = 3 + 3x2
3x2 + (4 + -2x) = 3 + 3x2

Reorder the terms:
4 + -2x + 3x2 = 3 + 3x2

Add '-3x2' to each side of the equation.
4 + -2x + 3x2 + -3x2 = 3 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
4 + -2x + 0 = 3 + 3x2 + -3x2
4 + -2x = 3 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
4 + -2x = 3 + 0
4 + -2x = 3

Solving
4 + -2x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -2x = 3 + -4

Combine like terms: 4 + -4 = 0
0 + -2x = 3 + -4
-2x = 3 + -4

Combine like terms: 3 + -4 = -1
-2x = -1

Divide each side by '-2'.
x = 0.5

Simplifying
x = 0.5

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